Monday, May 19, 2008

Geometry Problem 87



See complete Problem 87
Area of Quadrilateral and Midpoints of Diagonals. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.
at

1 comment:

  1. c .t . e. oJanuary 14, 2010 at 12:55 PM

    S BCNA =? S BCDM
    ABM+BMC+MNC+AMN =? BMC+MNC+CND+MND (AM=MC=>ABM=BMC)
    BMC+AMN =? CND+MND
    BMC+MNC =? CND+MND ( AM=MC=>MNC=AMN)
    BMNC =? MNCD
    BMN+BNC =? MND+NDC but BN=ND=>BMN=MND & BNC=NCD
    => BMN+BNC = MND+NDC or
    S1 = S2

    S3=BMC+MNC but BMC=ABM & MNC=AMN
    => S3 = 1/2 S1

    BCNA =? CDAN
    ABN+BNC =? AND+NDC but ABN = AND & BNC = NCD (N midpo)
    ABN+BNC = AND+NDC

    or S1 = 1/2 S

    ReplyDelete

Share your solution or comment below! Your input is valuable and may be shared with the community.