Monday, May 19, 2008

Elearn Geometry Problem 75



See complete Problem 75
Three Intersecting Circles, Cyclic Quadrilateral, Angles. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.
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4 comments:

  1. AnonymousJune 1, 2008 at 8:48 AM

    What points are M and N?
    If N is the point where ED meets AH, why is it on circle 5?

    ReplyDelete
  2. Antonio GutierrezJune 1, 2008 at 12:56 PM

    Thank you for your comment:
    Line AH and circle 3 meet at M, Line DE and circle 5 meet at N.

    The graphic was updated.

    Thank you.

    ReplyDelete
  3. c .t . e. oMarch 8, 2010 at 11:29 AM

    ang EAH = ang EBM ( AEHD cyclic, arc EFM )
    ang EDH = ang NCH ( NCDH cyclic. arc HGN

    EAH = EAD ( from P 73, AEHD cyclic )
    =>
    EBM = NCH
    =>
    PBQ = PCQ ( as vertikal angles )
    from
    geometry help P39, 16.2

    PBCQ cyclic

    ReplyDelete
  4. MarcoDecember 12, 2022 at 11:27 PM

    Join DH and by the result of problem 74, BCQP is a cyclic quad (converse of < in same seg.)

    ReplyDelete

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