tag:blogger.com,1999:blog-6933544261975483399.post6863891497621689320..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Elearn Geometry Problem 133Antonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger3125tag:blogger.com,1999:blog-6933544261975483399.post-33281287178856835622021-03-16T15:06:47.966-07:002021-03-16T15:06:47.966-07:00Considering Pappu's hexagon Theorem A,D,B and ...Considering Pappu's hexagon Theorem A,D,B and A,C,F are two sets of collinear points. As B,E,C are collinear D,E,F should be collinear to form the pappus line AE.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-24140654890134917232013-09-17T15:32:24.105-07:002013-09-17T15:32:24.105-07:00- P is on AC such that BP bisects <B.
- It is k...- P is on AC such that BP bisects <B.<br />- It is known that P is the harmonic conjugate of F w/r AC.<br />In conclusion, F-E-D must be colinear.<br />Editorhttps://www.blogger.com/profile/18079120609888942700noreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-34768314435792791132008-07-05T17:35:00.000-07:002008-07-05T17:35:00.000-07:00AE is an interior bisector of angle ABE/EC = AB/AC...AE is an interior bisector of angle A<BR/>BE/EC = AB/AC<BR/>CD is an interior bisector of angle C<BR/>AD/DB = AC/BC<BR/>AE is an exterior bisector of angle B<BR/>FA/FC = AB/BC<BR/>therefore<BR/>BD/DA * AF/FC * CE/EB = BC/AC * AB/BC * AC/BC = 1<BR/>therefore<BR/>D, E, F are collinear points<BR/>Magdy Essaftyمجدى الصفتىhttps://www.blogger.com/profile/16618039543014798443noreply@blogger.com