tag:blogger.com,1999:blog-6933544261975483399.post5520056943240729866..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Geometry Problem 1084: Circle, Chord, Radius, Diameter, Parallel lines, 45 Degrees, Metric RelationsAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-6933544261975483399.post-12300055573445199472015-02-15T07:19:06.359-08:002015-02-15T07:19:06.359-08:00Join AD, BE, AE.
Then ACDB and BCDE are isosceles...Join AD, BE, AE. <br />Then ACDB and BCDE are isosceles trapeziums. <br /><br />Since ∠CBE = ∠BCD = 45°, <br />thus ∠ABE = 90°. i.e. AE is diameter and AE=2r. <br /><br />Now since BE=CD=c, so in ΔABE, a²+c²=4r². <br />Also since AD=BC=b, so in ΔADE, b²+d²=4r². Jacob HA (EMK2000)https://www.blogger.com/profile/17238561555526381028noreply@blogger.com