tag:blogger.com,1999:blog-6933544261975483399.post5268193877387764270..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Problem 610: Intersecting Circles, Radius, Parallel, Common Tangent, Angle, 90 DegreesAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-6933544261975483399.post-27988897574492070042011-05-31T06:59:02.398-07:002011-05-31T06:59:02.398-07:00AG/GB =AE/BF=AC/BC
So CG bisects angle ACB interna...AG/GB =AE/BF=AC/BC<br />So CG bisects angle ACB internally <br />AH parallel BM<br />AN/BN = AH/BM =AC/BC<br />So CH bisects angle ACB externally<br />Therefore angle GCH = 90 degreesPravinhttps://www.blogger.com/profile/05947303919973968861noreply@blogger.com