tag:blogger.com,1999:blog-6933544261975483399.post5173496463665029860..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Geometry Problem 90Antonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-6933544261975483399.post-75069906310855248662016-04-27T14:34:33.490-07:002016-04-27T14:34:33.490-07:00Area triangle ABC is (ABC) then (BMD)=(ABD)-(ABM)-...Area triangle ABC is (ABC) then (BMD)=(ABD)-(ABM)-(AMD).But (MEN)=(MED)-(NED)-(NMD)=(MEC)+(MCD)-(BED)/2-(BMD)/2=(AEC)/2+(ACD)/2-(BED)/2-(ABD)/2+(ABM)/2+(AMD)/2=(AED)/2-(BED)/2-<br />(ABD)/2+(ABM)/2+(AMD)/2=(ABD)/2-(ABD)/2+(ABM)/2+(AMD)/2=(ABC)/4+(ACD)/4=<br />(ABCD)/4. <br />APOSTOLIS MANOLOUDIShttps://www.blogger.com/profile/15561495997090211148noreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-49390438797949094582008-09-05T10:54:00.000-07:002008-09-05T10:54:00.000-07:00Let X be the mid-pt of BC,XM//BA and XN//CD,[EBM]+...Let X be the mid-pt of BC,<BR/>XM//BA and XN//CD,<BR/>[EBM]+[ENC]=[EBX]+[EXC]=[EBC]<BR/>S_1=[BMNC]=1/2[BANC]=1/2*S/2=S/4Anonymousnoreply@blogger.com