tag:blogger.com,1999:blog-6933544261975483399.post297592329822059396..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Problem 380. Triangle, Excenter, Parallel to a side, Angle, CongruenceAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-6933544261975483399.post-82898335645532642152021-03-29T15:02:32.723-07:002021-03-29T15:02:32.723-07:00Isosceles Tr. AFE => AF=FE
Isosceles Tr. CGE ...Isosceles Tr. AFE => AF=FE <br />Isosceles Tr. CGE => CG=GE<br />FG=FE-GE=AF-CGSailendra Thttps://www.blogger.com/profile/12056621729673423024noreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-12923450094067230502009-12-18T12:26:39.597-08:002009-12-18T12:26:39.597-08:00AE as bisector, and AC // FE give AF = FE, so have...AE as bisector, and AC // FE give AF = FE, so have to prove CG = GE<br /><br />CE is bisector of ang GCP ( EP perpendicular to AC )<br />=> ang GCE = ang ECP (1)<br />ang ECP = ang CEG (2) ( CP // GE )<br />from 1 and 2 <br /><br />ang GCE = ang GEC<br />=> GC = GEc .t . e. onoreply@blogger.com