tag:blogger.com,1999:blog-6933544261975483399.post2181796573922866567..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Problem 534: Right Triangle, Squares, Perpendicular, Dissection, AreasAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-6933544261975483399.post-5809423698344816092010-11-01T08:54:07.309-07:002010-11-01T08:54:07.309-07:00A1=A2=A3=A4=A5 same base altitude and ASA
▲ABH ~ ...A1=A2=A3=A4=A5 same base altitude and ASA<br />▲ABH ~ ▲HKC => a/c = (a√2 - BH)/BH<br />=> BH = (a²√2)/(a+c)<br />=> SA3 = (EM∙1/2AD)/2 <br /><br />=>SA3 = ac²/(2(a+c))c .t . e. onoreply@blogger.com