tag:blogger.com,1999:blog-6933544261975483399.post2026100344051491535..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Geometry Problem 948: Intersecting Circles, Secant, Cyclic Quadrilateral, Concyclic PointsAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger4125tag:blogger.com,1999:blog-6933544261975483399.post-63711514220872137012020-02-15T09:08:42.087-08:002020-02-15T09:08:42.087-08:00External angle at F = < FD1D2 + < FD2D1 = &l...External angle at F = < FD1D2 + < FD2D1 = < ABC1 + < ABC2 = < C1BC2 and the result follows<br /><br />Sumith Peiris<br />Moratuwa<br />Sri LankaSumith Peirishttps://www.blogger.com/profile/06211995240466447227noreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-84515751889379058152016-10-17T22:28:17.434-07:002016-10-17T22:28:17.434-07:00To show that C2 and D2 are the image of C1 and D1...To show that C2 and D2 are the image of C1 and D1 in the transformation S(B, k,θ) we need to show that ∠C1BC2=∠D1BD2 and BC2/BC1= BD2/BD1 . <br /><br />Peter Tran<br />Peter Tranhttps://www.blogger.com/profile/02320555389429344028noreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-53976273885551428462013-12-24T07:13:36.893-08:002013-12-24T07:13:36.893-08:00∠D₁C₁B=∠D₁AB deoareceBD₁C₁A concyclic,∠D₁AB.+∠D₂AB...∠D₁C₁B=∠D₁AB deoareceBD₁C₁A concyclic,∠D₁AB.+∠D₂AB=180=>∠D₂C₂B=∠D₁C₁B si BC₁FC₂ concyclic. ion radunoreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-15497464421147098272013-12-21T17:38:58.285-08:002013-12-21T17:38:58.285-08:00Let S(B, k, θ) be a homothetic rotation transforma...Let S(B, k, θ) be a homothetic rotation transformation, <br />centered at B, such that C₁→C₂, D₁→D₂. <br /><br />Then ∠D₁C₁B=∠D₂C₂B. <br />Hence, BC₁FC₂ are concyclic. Jacob HA (EMK2000)https://www.blogger.com/profile/17238561555526381028noreply@blogger.com