tag:blogger.com,1999:blog-6933544261975483399.post1765247733995598056..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Problem 568: Triangle, Excircles, Tangency Point, CongruenceAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-6933544261975483399.post-42330068766491443132021-01-14T13:59:59.586-08:002021-01-14T13:59:59.586-08:00https://photos.app.goo.gl/ZbmRaEjfCNtP2yLX8https://photos.app.goo.gl/ZbmRaEjfCNtP2yLX8c.t.e.o.https://www.blogger.com/profile/16937400830387715195noreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-70212239703018706092011-01-17T19:19:30.495-08:002011-01-17T19:19:30.495-08:00http://img10.imageshack.us/img10/6161/problem568.p...http://img10.imageshack.us/img10/6161/problem568.png<br /><br />BE and BD are external angle bisector of angle (ABC) ( see attached picture)<br />So D,B,E are collinear and angle(DBF)= angle (GBE) ( half of vertical angles)<br />So angle(FDB)=angle(BEG) ( complement angles to congruence angles)<br />Triangles DHE is isosceles and DH=EH<br /><br />Peter TranPeter Tranhttps://www.blogger.com/profile/02320555389429344028noreply@blogger.com