tag:blogger.com,1999:blog-6933544261975483399.post1706573539556637202..comments2024-03-29T17:38:24.729-07:00Comments on Go Geometry (Problem Solutions): Elearn Geometry Problem 113Antonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-6933544261975483399.post-22839352616144771432010-03-14T20:52:28.134-07:002010-03-14T20:52:28.134-07:00AD = CG = s - AC ...........(s = 1/2 perimeter)
[I...AD = CG = s - AC ...........(s = 1/2 perimeter)<br />[IAD]= 1/2 . r . AD .......( r = inradius )<br />[ICG]= 1/2 . r . CG .......( r = inradius )<br />obviuos that [IAD] = [ICG]<br /><br />With the same way , can be proved that :<br />[IBE]=[ICH]and [IBF]=[IAM]<br /><br />Teddy A D (wteddyad@yahoo.com)Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-63259053722912244882010-01-03T02:19:04.055-08:002010-01-03T02:19:04.055-08:00MA=BF=p-c
DA=CG=p-b
CH=BE=p-a
all triangles have a...MA=BF=p-c<br />DA=CG=p-b<br />CH=BE=p-a<br />all triangles have altitude r<br />S1=S1'=0.5r(p-b)<br />S2=S2'=0.5r(p-a)<br />S3=S3'=0.5r(p-c)<br />.-.Anonymousnoreply@blogger.com