tag:blogger.com,1999:blog-6933544261975483399.post1503796842572871122..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Problem 628: Cyclic Quadrilateral, Congruence, Parallel LinesAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-6933544261975483399.post-15224892634934589262011-06-23T17:51:18.590-07:002011-06-23T17:51:18.590-07:00Isosceles Triangles ABE and DCF are equiangular
(v...Isosceles Triangles ABE and DCF are equiangular<br />(vertical angles at B and C being equal).<br />So <br /><AEB = <DFC,<br />and on taking supplements <br /><AED = <AFD <br />and thus<br />A,E,F,D are concyclic<br />Now <AFE = <ADB = <ACB<br />Hence EF // BCPravinhttps://www.blogger.com/profile/05947303919973968861noreply@blogger.com