tag:blogger.com,1999:blog-6933544261975483399.post1496486957606932244..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Problem 681: Gergonne Point, Triangle, Incircle, Tangency points, Concurrent lines, Semiperimeter, Ceva theoremAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-6933544261975483399.post-34684847875832286932011-11-02T18:14:50.734-07:002011-11-02T18:14:50.734-07:00AB':B'C = (s - a):(s - c)
CA':A'B ...AB':B'C = (s - a):(s - c)<br />CA':A'B = (s - c):(s - b)<br />BC':C'A = (s - b):(s - a)<br />Product = 1<br />By Ceva, the result follows.Pravinhttps://www.blogger.com/profile/05947303919973968861noreply@blogger.com