tag:blogger.com,1999:blog-6933544261975483399.post114997374169550917..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Elearn Geometry Problem 219: Rhombus, perpendiculars, arithmetic meanAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-6933544261975483399.post-17538346995102961072020-09-06T06:28:50.440-07:002020-09-06T06:28:50.440-07:00ABCD rhombus => GHO isoscele in H => OH=HG...ABCD rhombus => GHO isoscele in H => OH=HG=HM since GOM rectangle in O => OH=GM/2<br />Also, ABCD rhombus => FN distance between AB and CD is the same as that between AD and BC which is 2.OE<br />So a=OE-OH=(FN-GM)/2=(FG+MN)/2=(b+c)/2 QEDGreghttps://www.blogger.com/profile/14941282981782772132noreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-65898156805089222052009-01-08T07:56:00.000-08:002009-01-08T07:56:00.000-08:00clearly HM=HO=HG=x and OF=NF/2, soa+x=(b+c+2x)/2a=...clearly HM=HO=HG=x and OF=NF/2, so<BR/>a+x=(b+c+2x)/2<BR/>a=(b+c)/2Anonymousnoreply@blogger.com