Geometry Problem. Post your solution in the comment box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

## Thursday, April 13, 2017

### Geometry Problem 1332: Two Squares Side by Side, Triangle, Area

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Extend BC and GF at P. S=S(ABPG)-1/2 S(ABPG)-1/2 S(DEFG)-S(CPFE)-S(BCE)

ReplyDeleteS= 36

How did you calculate S(BCE)?

Deleteyou have nothing to calculate.

name AD = a

DeleteS = [(a+6)∙a] - [1/2(a+6)∙a] - [1/2(6∙6)] - [(a-6)∙6] - [1/2(a-6)∙a]

https://goo.gl/photos/ZgtosScujk4knoyr9

ReplyDeleteDraw rectangle BDHK as shown on the sketch

Area(BGE)= ½. EG*BK= ½. DH*EG= area(EDG)

= ½. 6*6= 18

Problem 1332

ReplyDeleteIs BD//EG then (EBG)=(EDG)=DE.DG/2=6.6/2=18.