Geometry Problem. Post your solution in the comment box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

## Thursday, February 23, 2017

### Geometry Problem 1318: Rectangle, Equilateral Triangle, Distances, Perpendicular, Measurement

Labels:
distance,
equilateral,
geometry problem,
measurement,
perpendicular,
rectangle

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Problm 1318

ReplyDeleteLet that the area of the triangle ABC is (ΑΒC) then apply that (ΑΕF)=(CBE)+(CFD) or

(EF.AH)/2=(CE.BG)/2+(CF.DM)/2 or AH=BG+DM or x=22-7=15.

APOSTOLIS MANOLOUDIS KORYDALLOS PIRAEUS GREECE

Following on from my proof for Problem 969 easily

ReplyDeleteS1 = S2 + S3

All 3 triangles have an equal base.

Hence x = 22-7= 15

Sumith Peiris

Moratuwa

Sri Lanka