Geometry Problem. Post your solution in the comment box below.

Level: Mathematics Education, High School, Honors Geometry, College.

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## Saturday, January 28, 2017

### Geometry Problem 1311: Inscribed Triangle, Circle, Circumcircle, Concyclic Points, Measurement

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We have AEFC is cyclic => Angle C= angle BEG=> Arc DB= Arc BG

ReplyDeleteAnd AB is an angle bisector of angle DAG

And DE/EG=AD/AG => x=AG= 16.5

AEFC are concircle, so <AED =<ACB, so arc AB= arc AD+ arc DB = arc AD + arc BG, SO arc DB=arc BG,so <GAB=<BaD,

ReplyDeleteso 12/8 = x/11

so x= 33/2