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Geometry Problem. Post your solution in the comment box below.Level: Mathematics Education, High School, Honors Geometry, College.Details: Click on the figure below.
We have AEFC is cyclic => Angle C= angle BEG=> Arc DB= Arc BGAnd AB is an angle bisector of angle DAGAnd DE/EG=AD/AG => x=AG= 16.5
AEFC are concircle, so <AED =<ACB, so arc AB= arc AD+ arc DB = arc AD + arc BG, SO arc DB=arc BG,so <GAB=<BaD,so 12/8 = x/11so x= 33/2