Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.
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Thursday, August 18, 2016
Geometry Problem 1248: Triangle, Circumcircle, Circle, Diameter, Orthocenter, Altitude, Parallel Lines
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Connect KC,
ReplyDeleteQuadrilateral AEDC is cyclic => ∠ (BED)= ∠ (ACB) .. ( both angles supplement to ∠ (AED))
we have ∠ (BAC)= ∠ (BKC) => ∠ (ABF)= ∠ (KBC)
so triangle BEG similar to BCM and triangles BEH similar to BCK …( case AA)
and we have BG/BM=BE/BC=BH/BK
so BG/BH=BM/BK
and GM//HK
add sketch of problem 1248
ReplyDeletehttps://photos.app.goo.gl/2rCpcFijxxBSHph78