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Geometry Problem. Post your solution in the comment box below.Level: Mathematics Education, High School, Honors Geometry, College.Click the figure below to view more details of problem 1231.
https://goo.gl/photos/eZPPUPkAJ3njjb2E7Draw OD ⊥ to AC ( D is on the circle O)D is the midpoint of arc ACsince BI is the angle bisector of ∠(ABC) => B, I, D are collinearTriangle BOD is isoceles => ∠(OBI)=∠(ODI)but ∠(ODI)=∠(HBI) => ∠(HBI)=∠(OBI) => BI is the angle bisector of ∠( HBO)
see correct link to this problem below:https://goo.gl/photos/NtEqqUcJsf3GfQgm6Peter Tran
Prøblem 1231< ABI = < CBI ......(1)< ABH = < CBO = 90-A ....(2)(1) - (2) gives the required result Sumith PeirisMoratuwaSri Lanka