Geometry Problem. Post your solution in the comment box below.

Level: Mathematics Education, High School, Honors Geometry, College.

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## Friday, January 29, 2016

### Geometry Problem 1183: Parallelogram, Diagonals, Circle, Tangent Line

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Let AC meet BD at H

ReplyDeleteObserve that radius of circle A= radius of circle C

so AE=CF => HE=GF

H is the midpoint of EF and BD => EBFD is a parallelogram

tr ABD congr tr CBD =>altitudes A to tg point congr to C to tg point

ReplyDelete=> Ra=Rb => EA=CF =>BD and EF halve each other