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Geometry Problem. Post your solution in the comment box below.Level: Mathematics Education, High School, Honors Geometry, College.Click the figure below to view more details of problem 1183.
Let AC meet BD at H Observe that radius of circle A= radius of circle Cso AE=CF => HE=GFH is the midpoint of EF and BD => EBFD is a parallelogram
tr ABD congr tr CBD =>altitudes A to tg point congr to C to tg point=> Ra=Rb => EA=CF =>BD and EF halve each other