Online Geometry theorems, problems, solutions, and related topics.
Geometry Problem. Post your solution in the comment box below.Level: Mathematics Education, High School, Honors Geometry, College.Click the figure below to view more details of problem 1181.
Ang B1=Ang B2 (BO bisector), => D1=D2 => AB=BCBut BC-BF=3 => x=3
BD is a diameter of circle ABCD and also bisects < ABC. Hence Tr. s ABD and BCD are congruent ASA. So AB = BC Hence x = BC - BFNow BC + 7 = BF + 10 since BCEF is a tangential quadrilateral So BC - BF = 3 and hence x = 3Sumith PeirisMoratuwaSri Lanka
Triangles BCD and BAD are right triangles ∠ (CBD)= ∠ (ABD) => Tri BCD congruence to BAD and BA=BCBCEF is a tangential quadrilateral soBF+CE=EF+BC => BC-BF=CE-EF= 10-7=3BA-BF=FA=3