Thursday, January 14, 2016

Geometry Problem 1178: Triangle, Internal Angle Bisector, Metric Relations

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to view more details of problem 1178.

Online Math: Geometry Problem 1178: Triangle, Internal Angle Bisector, Metric Relations.

2 comments:

  1. Lets assume AD extended meets circumcircle of Tr.ABC at point E.
    Assuming DE=x, we have d.x= BD.CD
    BD = ac/(b+c), CD = ab/(b+c)
    Also Tr. ACD is similar to Tr.AEB
    We have d/c=b/(d+x) we get
    d^2 = bc - dx or d^2 = bc - BD.CD
    Substituting values of BD and CD we get required expression.

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    Replies
    1. Perhaps the easiest way of doing this thro' pure geometry alone

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