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Geometry Problem. Post your solution in the comments box below.Level: Mathematics Education, High School, Honors Geometry, College.Click the diagram below for more details.
Let I is incenter of triangle ABCLet BI meet AC at LObserve that EBDI is a complete quadrangle so L, F are harmonic conjugate points of A and C.Since BL is an internal bisector of angle ABC So BL is external bisectors of angle ABC and FH=FG
this problem need1) BF bisector of CBH2) IBF = 903) BI // GH4) GB = BHIt is possible in another construcsion included AB > BC