Saturday, February 21, 2015

Geometry Problem 1087: Tangent Circles, Parallel, 15 Degrees, Angle

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Click the diagram below to enlarge it.

Online Math: Geometry Problem 1087: Tangent Circles, Parallel, 15 Degrees, Angle.

3 comments:

  1. Obviously ∠COA=45°.

    Now let D be the foot of perpendicular from B to OA.
    Then BD/OB = CQ/OA = 1/2, thus ∠BOA=30°.

    Hence, ∠COB=15°.

    ReplyDelete