Online Geometry theorems, problems, solutions, and related topics.
Geometry Problem. Post your solution in the comments box below.Level: Mathematics Education, High School, Honors Geometry, College.Click the figure below to view the complete problem 1047.
AG and HC meet at P, and HC and AB meet at Q. AQ=AH*CD/HD. Then AP/PG=AQ/CG=(AH*CD/HD)/CG=(AH*CD)/(HD*CG).AG and BO meet at P', and BO and CD meet at T. GT=(OG=HD)*(BE=CG)/(EO=AH)Then AP'/P'G=(BA=CD)/GT=CD/(HD*CG/AH)=(AH*CD)/(HD*CG)It has been shown that BO and HC meet at the same point of AG.