Geometry Problem. Post your solution in the comments box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to view the complete problem 1037.

## Saturday, August 2, 2014

### Geometry Problem 1037: Triangle, Three equal Incircles, Tangent lines, Inradius, Length

Subscribe to:
Post Comments (Atom)

Let r2 is the inradius of triangle A2B2C2

ReplyDeleteNote that incenter of triangle ABC is coincided to incenter of triangle A2B2C2

So r=d+r2

But r2=r1 per problem 1036

So r1= r-d