Saturday, May 10, 2014

Geometry Problem 1013: Square, Line through the Center, Perpendicular, Distance, Metric Relations

Geometry Problem. Post your solution in the comments box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to enlarge the figure of problem 1013.

Online Geometry Problem 1013: Square, Line through the Center, Perpendicular, Distance, Metric Relations.

Posted by Antonio Gutierrez at 11:18 PM
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2 comments:

  1. Ivan BazarovMay 11, 2014 at 6:35 AM

    Triangles EOA-FBO and GOD-HCO are congruent by ASA, making EO=FB and GO=HC. Therefore AE^2+(FB=EO)^2+GD^2+(CH=GO)^2=AO^2+OD^2=AD^2

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  2. Jacob HA (EMK2000)May 11, 2014 at 6:59 AM

    By symmetry,
    AE=OF=OG=CH, BF=OE=OH=DG.

    AE² + BF² + CH² + DG²
    = AE² + OE² + OG² + DG²
    = OA² + OD²
    = AD²

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