Geometry Problem. Post your solution in the comments box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 1009.

## Friday, April 25, 2014

### Geometry Problem 1009: Tangent Circles, Common External Tangent, Common Internal Tangent, Arithmetic Mean

Labels:
arithmetic mean,
circle,
common tangent

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Since EA=ET=EB, FC=FT=FD,

ReplyDeleteAlso AD//BC (ABCD is trapezium),

Thus EF=(AD+BC)/2.