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Geometry Problem. Post your solution in the comments box below.Level: Mathematics Education, High School, Honors Geometry, College.Click the figure below to view the complete problem 992
http://s25.postimg.org/7jzp7p7zz/Pro_992.pngDraw altitude CE of isosceles triangle ABCWe haves angles as shown on the sketchD is the center of incircle of triangle AFC => angle DCF=10So x= 180-60-10= 110
If E is the circumcenter of tr. ABD, then tr. ADE is equilateral (1) and, easily, tr. ACE and BEC are isosceles; with (1) CD is bisector of <ACE, making <BCD=30,hence <BDC=110.Best regards