Geometry Problem

Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 965.

## Wednesday, January 22, 2014

### Geometry Problem 965: Triangle, Cevians, Midpoint, Circumcircle, Circle, Tangent Line, Metric Relations

Labels:
cevian,
circle,
circumcircle,
metric relations,
midpoint,
tangent,
triangle

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we have FH= 25/2=12.5 and FH//CD

ReplyDeleteFG//EA and FG= .5*EA

And ∠ (GHF)= ∠ (EFG)= ∠ (BEF)

Triangle GFH similar to DBE ….( case AA)

FH/EB=FG/BD => FG=12.5 x 14/40= 4.375

So EA= 8.75