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Geometry Problem. Post your solution in the comments box below.Level: Mathematics Education, High School, Honors Geometry, College.Click the figure below to enlarge the problem 944.
Since FE//GK, so HE/HK = HF/HG. Since FJ//ED, so HF/HG = HJ/HD. Thus, HE/HK = HJ/HD, hence JE//DK.
Correction: FJ//GD in line 2.
<FHJ=<FEJ=<GKD of cyclic quadrilaterals FJEH and GDKH. But EF//GK so JE//DK.