Geometry Problem. Post your solution in the comments box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to enlarge the problem 944.

## Wednesday, December 18, 2013

### Geometry Problem 944: Triangle, Orthocenter, Altitude, Perpendicular, 90 Degrees, Parallel Lines

Labels:
altitude,
orthocenter,
parallel,
perpendicular,
triangle

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Since FE//GK, so HE/HK = HF/HG.

ReplyDeleteSince FJ//ED, so HF/HG = HJ/HD.

Thus, HE/HK = HJ/HD, hence JE//DK.

Correction: FJ//GD in line 2.

Delete<FHJ=<FEJ=<GKD of cyclic quadrilaterals FJEH and GDKH. But EF//GK so JE//DK.

ReplyDelete