Saturday, August 10, 2013

Problem 911: Right Triangle, Double Angle, Triple Angle, Concyclic Points, Cyclic Quadrilateral

Geometry Problem
Post your solution in the comment box below

Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 911.

Online Geometry Problem 911: Right Triangle, Double Angle, Triple Angle, Concyclic Points, Cyclic Quadrilateral.

3 comments:

  1. In ΔABC and ΔBCD,
    ∠BCA = 90° − 2α
    ∠BDC = 90° − 3α

    In ΔBCE,
    ∠EBC = 90°
    ∠BEC = 90° − 3α = ∠BDC

    Hence, B, C, D, E concyclic.

    ReplyDelete
  2. < EBD = 90- @ = < ECD since < BCD = 90 + 2@ and so the result follows

    Sumith Peiris
    Moratuwa
    Sri Lanka

    ReplyDelete
  3. Triangles ABD and ACE similar => AB.AE=AC.AD

    ReplyDelete