Geometry Problem

Post your solution in the comment box below

Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 911.

## Saturday, August 10, 2013

### Problem 911: Right Triangle, Double Angle, Triple Angle, Concyclic Points, Cyclic Quadrilateral

Labels:
concyclic,
cyclic quadrilateral,
double angle,
right triangle,
triple

Subscribe to:
Post Comments (Atom)

In ΔABC and ΔBCD,

ReplyDelete∠BCA = 90° − 2α

∠BDC = 90° − 3α

In ΔBCE,

∠EBC = 90°

∠BEC = 90° − 3α = ∠BDC

Hence, B, C, D, E concyclic.

< EBD = 90- @ = < ECD since < BCD = 90 + 2@ and so the result follows

ReplyDeleteSumith Peiris

Moratuwa

Sri Lanka