Geometry Problem. GeoGebra, HTML5 Animation for iPad and Nexus.

Post your solution in the comments box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the dynamic geometry demonstration of problem 898.

## Monday, July 8, 2013

### Problem 898: Intersecting Circles, Common External Tangent, Secant, Circumcenter, Collinear Points

Labels:
collinear,
common tangent,
intersecting circles,
secant

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Power of H to circle O= HC^2=HA.HB

ReplyDeletePower of H to circle O1=HD^2=HA.HB

So HC=HD => H is the midpoint of CD

Per result of problem 897, CGD is an isosceles triangle

So HG is the perpen. bisector of CD and H, O2 and G are collinear