Geometry Problem. GeoGebra, HTML5 Animation for iPad and Nexus.

Post your solution in the comments box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the dynamic geometry demonstration of problem 896.

## Thursday, July 4, 2013

### Problem 896: Triangle, Orthocenter, Midpoint, Median, Intersecting Circles, Diameter, Collinear Points

Labels:
collinear,
diameter,
intersecting circles,
midpoint,
orthocenter,
triangle

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quadrilateral BIJC is cyclic

ReplyDeleteSo HB.HJ=HI.HC

But HB.HJ= power of H to circle D

And HI.HC is the power of H to circle E

So H must be on axis of equi-power of circles D and E

F, H and G are collinear