Online Geometry theorems, problems, solutions, and related topics.
Geometry ProblemLevel: Mathematics Education, High School, Honors Geometry, College.Click the figure below to see the complete problem 849.
Is ,AD=DE=EC and EM perpendicular of the AC with EM=AB=c.Then ABME,is ,a parallelogram and ADM is, diagonal. So, angle EBM= angle AEB=βThe triangle DMC is isosceles and rectangular.So,the ABMC , is a cyclic quadrilateral,therefore ,angle AMB=ACB=α. Βut ,from the triangle ΒΔΜ we ,angle EBM+ angle AMB=α+β=45.Because (problem 848), β= 26,5 degrees ,then α=18,5 degreesImage: http://img526.imageshack.us/img526/5597/geogebra3.png
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