## Saturday, January 26, 2013

### Problem 848: Special Right triangle, Catheti or legs ratio 1:2, 26.5 Degrees. Double angle

Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 848.

1. we have tan c=c/2c
then tanc =0.5
c = shift tan(0.5)= 26.56

2. Draw a perpendicular BD from B to AC and the Let the two circles intersect in E.
Now, AC = sqrt(5)*c while BD * AC = AB * BC or BD = (c * 2c)/(sqrt(5)*c) = 2c/sqrt(5)
We can say that /_ACB//_ECB ~= BD/BE = 2/sqrt(5) or /_ACB = /_ECB * 2/sqrt(5) = 60/sqrt(5)
or /_ ACB ~= 26.83281

3. I did not get this problem
dear antonio gutierrez can u post this soln
my teachers the problem is immpossible

1. Dear Pranav,
I apologize for the problem (Site Temporarily Unavailable), I am looking for a solution. In the meantime you can see this problem at http://agutie.homestead.com/files/geometry/p848-special-right-triangle-cathetus-1-2-angle-26.5-degrees.htm

4. i did not get the solution