Monday, December 5, 2011

Problem 699: Equilateral Triangle, Circle, Circular Segment, Midpoint, Metric Relations

Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 699.

Online Geometry Problem 699: Equilateral Triangle, Circle, Circular Segment, Midpoint, Metric Relations.

2 comments:

  1. http://img821.imageshack.us/img821/6871/problem699.png
    BD cut EF at G ( see picture)
    Note that DG=OG (angle ABC=60)
    Triangle ABG similar to tri. EDG with ratio =BG/DG=3
    So x= AB/3= 4
    Peter Tran

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  2. DAC = 30, AED = 120 imply ADE = 30
    So AE = ED = x
    FC = DF = x (by symmetry)
    So x = AE = EF = FC = AC/3 = 4

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