Geometry Problem

Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 681.

## Tuesday, November 1, 2011

### Problem 681: Gergonne Point, Triangle, Incircle, Tangency points, Concurrent lines, Semiperimeter, Ceva theorem

Labels:
Ceva's theorem,
concurrent,
Gergonne,
incircle,
tangency point,
triangle

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AB':B'C = (s - a):(s - c)

ReplyDeleteCA':A'B = (s - c):(s - b)

BC':C'A = (s - b):(s - a)

Product = 1

By Ceva, the result follows.