Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to see the complete problem 623.
Thursday, June 16, 2011
Problem 623: Triangle, Incenter, Excenter, Incircle, Excircle, Concyclic Points
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∠IBE = B/2 + (180°-B)/2 = 90°
ReplyDeleteSimilarly ∠ICE = 90°
So ∠IBE + ∠ICE = 180° and I,B,E,C are concyclic
internal and external angle bisector are perpendicular; so the result follows
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