Geometry Problem

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## Monday, May 30, 2011

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## Monday, May 30, 2011

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Problem 610: Intersecting Circles, Radius, Parallel, Common Tangent, Angle, 90 Degrees

Online Geometry theorems, problems, solutions, and related topics.

Labels:
90,
common tangent,
degree,
intersecting circles,
parallel,
radius

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AG/GB =AE/BF=AC/BC

ReplyDeleteSo CG bisects angle ACB internally

AH parallel BM

AN/BN = AH/BM =AC/BC

So CH bisects angle ACB externally

Therefore angle GCH = 90 degrees