Geometry Problem

Click the figure below to see the complete problem 489 about Parallelogram, Triangle, Quadrilateral, Area.

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Complete Problem 489

Level: High School, SAT Prep, College geometry

## Sunday, August 1, 2010

### Problem 489: Parallelogram, Triangle, Quadrilateral, Area

Labels:
area,
parallelogram,
quadrilateral,
triangle

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Tr. EFC/Tr.EFD = EC/ED = EB/EF as BC//FD. But EB/EF=DA/DF as AB//DC. So Tr. EFC/Tr.EFD =DA/DF=Tr.EAD/Tr.EFD or Tr. EFC = Tr.EAD and thus Tr. EFC - Tr. EGC = Tr.EAD - Tr.EGC or A2 = A1 as reqd.

ReplyDeleteVihaan, Dubai

▲AFB ~ ▲BCE => FD/AF = h/h2 (h, h2 alt FDE, FDC )

ReplyDelete=> FD∙h2 = AF∙h => SFDC = SAFE =>

SAGCD = SFGE