Friday, July 23, 2010

Problem 478: Triangle, Sides, Circumradius, Circumcenter, Circumcircle

Geometry Problem
Click the figure below to see the complete problem 478 about Triangle, Sides, Circumradius, Circumcenter, Circumcircle.

Problem 478: Triangle, Sides, Circumradius, Circumcenter, Circumcircle
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Complete Problem 478

Level: High School, SAT Prep, College geometry


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1 comment:

  1. Let BO intersect circle O at D
    We have DA=SQRT(BD^2-AB^2)=SQRT(4R^2-c^2)
    DC=SQRT(4R^2-a^2)
    Apply Ptolemy’s theorem to Cyclic quadrilateral ABCD :
    AC.BD=AB.CD+BC.AD
    Replace values of AB, CD, BC, AD ,AC and BD in above equation we will get the result

    Peter Tran

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