Geometry Problem

Click the figure below to see the complete problem 462 about Square, Arcs, 90 Degrees, Circle, Tangent, Radius, Measurement.

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Complete Problem 462

Level: High School, SAT Prep, College geometry

## Wednesday, May 26, 2010

### Problem 462: Square, Arcs, 90 Degrees, Circle, Tangent, Radius, Measurement

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FE=x;AE=a-x;DE=a+x

ReplyDeletesin(FAE)=cos(EAD)=x/(a-x)

in triangle ADE

DE²=AE²+AD²-2AE.AD.cos(EAD)

(a+x)²=(a-x)²+a²-2ax

a²-6ax=0

x=a/6

.-.

AE= a-x DE=a+x. drop a perpendicular from E toAD meeting AD @ J

ReplyDelete(a-x)^2= EJ^2+x^2

(a+x)^2= EJ^2+(a-x)^2

subtract

(a-x)^2 -(a+x)^2 = X^2- (a-x)^2

Simplify

a^2-6ax=0

a^2 - 6ax =0

x= a/6