Wednesday, May 26, 2010

Problem 462: Square, Arcs, 90 Degrees, Circle, Tangent, Radius, Measurement

Geometry Problem
Click the figure below to see the complete problem 462 about Square, Arcs, 90 Degrees, Circle, Tangent, Radius, Measurement.

Problem 462: Square, Arcs, 90 Degrees, Circle, Tangent, Radius, Measurement
See also:
Complete Problem 462

Level: High School, SAT Prep, College geometry

2 comments:

  1. FE=x;AE=a-x;DE=a+x
    sin(FAE)=cos(EAD)=x/(a-x)
    in triangle ADE
    DE²=AE²+AD²-2AE.AD.cos(EAD)
    (a+x)²=(a-x)²+a²-2ax
    a²-6ax=0
    x=a/6
    .-.

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  2. AE= a-x DE=a+x. drop a perpendicular from E toAD meeting AD @ J
    (a-x)^2= EJ^2+x^2
    (a+x)^2= EJ^2+(a-x)^2
    subtract
    (a-x)^2 -(a+x)^2 = X^2- (a-x)^2
    Simplify
    a^2-6ax=0

    a^2 - 6ax =0
    x= a/6

    ReplyDelete