Geometry Problem

Click the figure below to see the complete problem 442 about Triangle, Median, Cevian, Transversal, Congruent Angles.

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Complete Problem 442

Level: High School, SAT Prep, College geometry

## Friday, April 30, 2010

### Problem 442: Triangle, Median, Cevian, Transversal, Congruent Angles

Labels:
angle,
cevian,
congruence,
median,
transversal,
triangle

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▲FGB ~ ▲BDC => FG/DC = BF/BC (α = α, ß = ß )

ReplyDelete▲BFJ ~ ▲ABC => FJ/AC = BF/BC (α = α, B common)

=>

FG/DC = FJ/AC

5/0.5 AC = (8+x)/AC

10 = 8 + x

x = 2

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just observe that BFGJ is similar to BCDA, than FG/GJ=CD/DA=1 and x=5-3=2

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