Wednesday, October 28, 2009

Problem 380. Triangle, Excenter, Parallel to a side, Angle, Congruence

Proposed Problem
Click the figure below to see the complete problem 380 about Triangle, Excenter, Parallel to a side, Angle, Congruence.

Problem 380. Triangle, Excenter, Parallel to a side, Angle, Congruence.
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Complete Geometry Problem 380
Level: High School, SAT Prep, College geometry

Posted by Antonio Gutierrez at 1:46 PM
Labels: , , , , , ,

2 comments:

  1. c .t . e. oDecember 18, 2009 at 12:26 PM

    AE as bisector, and AC // FE give AF = FE, so have to prove CG = GE

    CE is bisector of ang GCP ( EP perpendicular to AC )
    => ang GCE = ang ECP (1)
    ang ECP = ang CEG (2) ( CP // GE )
    from 1 and 2

    ang GCE = ang GEC
    => GC = GE

    ReplyDelete
  2. Sailendra TMarch 29, 2021 at 3:02 PM

    Isosceles Tr. AFE => AF=FE
    Isosceles Tr. CGE => CG=GE
    FG=FE-GE=AF-CG

    ReplyDelete

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