Wednesday, October 28, 2009

Problem 380. Triangle, Excenter, Parallel to a side, Angle, Congruence

Proposed Problem
Click the figure below to see the complete problem 380 about Triangle, Excenter, Parallel to a side, Angle, Congruence.

 Problem 380. Triangle, Excenter, Parallel to a side, Angle, Congruence.
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Complete Geometry Problem 380
Level: High School, SAT Prep, College geometry

1 comment:

  1. AE as bisector, and AC // FE give AF = FE, so have to prove CG = GE

    CE is bisector of ang GCP ( EP perpendicular to AC )
    => ang GCE = ang ECP (1)
    ang ECP = ang CEG (2) ( CP // GE )
    from 1 and 2

    ang GCE = ang GEC
    => GC = GE

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