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Click the figure below to see the complete problem 376 about Triangle, Internal Angle Bisector, Altitude.
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Complete Geometry Problem 377
Level: High School, SAT Prep
Tuesday, October 27, 2009
Problem 377: Triangle, Internal Angle Bisector, Altitude
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A+B+C=180 and B/2+alpha=90-A.
ReplyDeleteSo, (180-A-C)/2+alpha=90-A,
alpha=(C-A)/2.
alpha = B/2-(90-C)=B/2-A/2-B/2-C/2+C=(C-A)/2
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