Proposed Problem

Click the figure below to see the complete problem 374 about Triangle, Incenter, Internal Angle Bisectors.

See more:

Complete Geometry Problem 374

Level: High School, SAT Prep

## Tuesday, October 27, 2009

### Problem 374: Triangle, Incenter, Internal Angle Bisectors

Labels:
angle,
angle bisector,
incenter,
triangle

Subscribe to:
Post Comments (Atom)

A+B+C=180, since I is the incenter of the triangle ABC, alpha=90-B/2+90-C/2=A/2+90

ReplyDelete