Tuesday, October 27, 2009

Problem 374: Triangle, Incenter, Internal Angle Bisectors

Proposed Problem
Click the figure below to see the complete problem 374 about Triangle, Incenter, Internal Angle Bisectors.

 Problem 374: Triangle, Incenter, Internal Angle Bisectors.
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Complete Geometry Problem 374
Level: High School, SAT Prep

1 comment:

  1. A+B+C=180, since I is the incenter of the triangle ABC, alpha=90-B/2+90-C/2=A/2+90

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