Wednesday, September 30, 2009

Problem 361: Right triangle, Incircle, Incenter, Tangency points, Angle

Proposed Problem
Click the figure below to see the complete problem 361 about Right triangle, Incircle, Incenter, Tangency points, Angle.

Problem 361. Right triangle, Incircle, Incenter, Tangency points, Angle.
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Complete Problem 361
Level: High School, SAT Prep, College geometry

Posted by Antonio Gutierrez at 11:58 AM
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3 comments:

  1. We've angle AED = angle AED = (180-A)/2 = 90 -A/2
    Futher from Tr. FEC, α = angle AED - angle ACF =90-A/2-C/2 = angle B/2 since angs.(A+B+C)=180 deg. which, in turn, means that α = 90/2 = 45 deg.
    Vihaan: vihaanup@gmail.com

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  2. @vihaan
    Pls explain this step

    We've angle AED = angle AED = (180-A)/2 = 90 -A/2

    How do we get this?????

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  3. /_AED+/_ADE+/_A=180 but /_AED=/_ADE (equal tangents). So 2/_ADE+/_A=180 or /_ADE=/_AED=90- A/2
    Vihaan

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